Model 3 Man Leaves & Joins Practice Questions Answers Test With Solutions & More Shortcuts
TIME & WORK PRACTICE TEST [7 - EXERCISES]
Model 1 Basics On Time & Work
Model 2 Formula Method ‘M1D1W1 = M2D2W2’
Model 3 Man Leaves & Joins
Model 4 Working With Man, Woman, Child
Model 5 Split & Fraction Of Work
Model 6 Efficiency Of The Worker
Model 7 Working With Individual Wages
Question : 16 [SSC CGL Prelim 2004]
A and B can do a piece of work in 20 days and 12 days respectively. A started the work alone and then after 4 days B joined him till the completion of the work. How long did the work last ?
a) 20 days
b) 15 days
c) 6 days
d) 10 days
Answer »Answer: (d)
A’s 1 day’s work = $1/20$
A’s 4 days’ work = $4/20 = 1/5$
Remaining work = $1 - 1/5 = 4/5$
This part is completed by A and B together.
Now, (A + B)’s 1 day’s work = $1/20 + 1/12$
= ${3 + 5}/60 = 8/60 = 2/15$
Now, $2/15$ work is done by (A + B) in 1 day.
$4/5$ work is done in
= $15/2 × 4/5$ = 6 days.
Hence, the work lasted for 4 + 6 = 10 days.
Question : 17 [SSC CGL Prelim 2008]
A can do a piece of work in 18 days and B in 12 days. They began the work together, but B left the work 3 days before its completion. In how many days, in all, was the work completed?
a) 10 days
b) 9.6 days
c) 9 days
d) 12 days
Answer »Answer: (c)
Let the work be finished in x days.
According to the question,
A worked for x days while B worked for (x - 3) days
$x/18 + {x - 3}/12 = 1$
${2x + 3x - 9}/36 = 1$
5x - 9 = 36
5x = 45 ⇒ x = $45/5$ = 9
Hence, the work was completed in 9 days.
Using Rule 8(i) If A can do a work in 'x' days and B can do the same work in 'y' days and when they started working together, B left the work 'm' days before completion thentotal time taken to complete work is ${(y + m)x}/{x + y}$(ii) A leaves the work 'm' days before its completion then total time taken to complete work is = ${(x + m)y}/{x + y}$
Here, x = 18, y = 12, m = 3
Total time taken = $({y + m}/{x + y})x$
= $({12 + 3}/{18 + 12})$ × 18 = 9 days
Question : 18 [SSC CGL Prelim 1999]
A can complete a piece of work in 10 days, B in 15 days and C in 20 days. A and C worked together for two days and then A was replaced by B. In how many days, altogether, was the work completed ?
a) 10 days
b) 6 days
c) 8 days
d) 12 days
Answer »Answer: (c)
Work done by (A + C) in 2 days
= $2(1/10 + 1/20) = 2({2 + 1}/20) = 6/20 = 3/10$
Remaining work = $1 - 3/10 = 7/10$
(B + C)’s 1 day’s work
= $1/15 + 1/20 = {4 + 3}/60 = 7/60$
Time taken by (B + C) to finish $7/10$ part of the work
= $60/7 × 7/10$ = 6 days
Total time = 2 + 6 = 8 days
Question : 19 [SSC CGL Prelim 1999]
A and B can do a work in 18 and 24 days respectively. They worked together for 8 days and then A left. The remaining work was finished by B in :
a) 5$1/3$ days
b) 8 days
c) 10 days
d) 5 days
Answer »Answer: (a)
Since, A can finish the work in 18 days.
A’s one day’s' work = $1/18$
Similarly, B’s one day’s work = $1/24$
(A + B)’s 8 days’ work = $(1/18 + 1/24) × 8 = 7/72 × 8 = 7/9$
Remaining work = $1 - 7/9 = 2/9$
Time taken to finish the remaining work by B is $2/9 × 24 = 16/3 = 5{1}/3$ days
Using Rule 20A can do a certain work in 'm' days and B can do the same work in 'n' days. They worked together for 'P' days and after this A left the work, then in how many days did B alone do the rest of work ?Required time = ${mn - P(m + n)}/m$ dayswhen after 'P' days B left the work, then in how many days did A alone do the rest of work?Required time = ${mn - P(m + n)}/n$ days
Here, m = 18, n= 24 and p = 8
Required Time = ${18 × 24 - 8(18 + 24)}/18$
= ${432 - 336}/18 = 96/18$
= $16/3 = 5{1}/3$ days
Question : 20 [SSC CHSL 2010]
X alone can complete a piece of work in 40 days. He worked for 8 days and left. Y alone completed the remaining work in 16 days. How long would X and Y together take to complete the work ?
a) 14 days
b) 15 days
c) 16$2/3$ days
d) 13$1/3$ days
Answer »Answer: (d)
Part of the work done by X in 8 days.
=$8/40 = 1/5$
[Since, work done in 1 day = $1/40$]
Remaining work = $1 - 1/5 = 4/5$
This part of work is done by Y in 16 days.
Time taken by Y in doing 1 work
= ${16 × 5}/4$ = 20 days
Work done by X and Y in 1 day
= $1/40 + 1/20 = {1+2}/40 = 3/40$
Hence, both together will complete the work in $40/3$
i.e.$13{1}/3$ days.
IMPORTANT QUANTITATIVE APTITUDE EXERCISES
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Top 199+ Basic Time and Work Aptitude MCQs with Answers »
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Top 200+ Time and Work Problem Solving By Formula Method »
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New 189+ Time & Work MCQs Practice Test for BANK Exams »
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Top 199+ Time & Work MCQs: Men Women Child for BANK Exam »
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Top 199+ Time and Work Questions Test on Fraction of Work »
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Top 199+ Time and Work Efficiency Based Aptitude MCQ Quiz »
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New 299+ Time and Work Aptitude Test On Individual Wages »
Model 3 Man Leaves & Joins Shortcuts »
Click to Read...Model 3 Man Leaves & Joins Online Quiz
Click to Start..TIME & WORK SHORTCUTS AND TECHNIQUES WITH EXAMPLES
-
Model 1 Basics On Time & Work
Defination & Shortcuts … -
Model 2 Formula Method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man Leaves & Joins
Defination & Shortcuts … -
Model 4 Working With Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction Of Work
Defination & Shortcuts … -
Model 6 Efficiency Of The Worker
Defination & Shortcuts … -
Model 7 Working With Individual Wages
Defination & Shortcuts …
QUANTITATIVE APTITUDE CATEGORIES
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» Number System
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» Average
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» LCM & HCF
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» Percentage
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» Profit & Loss
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» Time & Work
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» Time & Distance
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» Trains
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» Compound Interest
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» Simplification
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» Discount
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» Power
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